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11.3 Constructing loci Construct (a) the locus of points equidistant from two given points; (b) the locus of points equidistant from two given parallel lines; (c) the locus of points at a given distance from a given circle whose radius is less than that distance.

cout.setf( ios::oct I ios::ios ); cout.width(l2);

12.11 Write a program that uses the set f ( ) , f i 11( ) , and width ( > functions to produce the following formatted output:

See Fig. 11-13.

10 11 12 A String Class.................................22 Inheritance....................................24 Streams........................................27 2 4 3

Fig. 11-13

The idea here is to use left-justify the titles in a field width of 60 columns, with I . I as the fill character padding the field on the right, so that the page numbers align at the end of the field: #include <iostream.h>

A point or points which satisfy two conditions may be found by drawing the locus for each condition. The required points are the points of intersection of the two loci.

main0 -t cout.setf(ios::left); cout.fill('.'); const int w = 60; cout.width(w); tout << "\t 10 A String Class" << "222\n"; cout.width(w); tout << "\t 11 Inheritance" << "244\n"; cout.width(w); tout << "\t 12 Streams" +c "273\n";

816 How is an individual array element passed to a procedure as an argument 817 When an array element is passed to a procedure as an element, must the corresponding argument in the procedure definition also be an array element Explain fully 818 What is a dynamic array How is a dynamic array declared 819 Once a dynamic array has been declared, how is its size specified Can a numeric variable or a numeric expression be used for the size specification 820 Can lower subscript limits and upper subscript limits both appear within a dynamic array size specification 821 When a dynamic array is redimensioned, what happens to the values previously assigned to the array elements 822 How can the values previously assigned to the elements of a dynamic array be retained when the array is redimensioned 8.

11.4 Locating points that satisfy two conditions On a map locate buried treasure that is 3 ft from a tree (T ) and equidistant from two points (A and B) in Fig. 11-14.

Write a function to reverse a string in place (Le., without duplicating all the characters).

void reverse(char* s) char temp; char* end = s + strlen(s) - 1; while (s c end) { temp = *s; *s++ = *end; *end-- = temp;

Fig. 11-14

What shou.ld the function prototype for the ends stream manipulator look like Write code that formats cou t so that floats are printed in scientific notation with 12-digit precision. Supplementary Programming Problems

The required loci are (1) the perpendicular bisector of AB and (2) a circle with its center at T and radius 3 ft. As shown, these meet in P1 and P2, which are the locations of the treasure. Note: The diagram shows the two loci intersecting at P1 and P2. However, there are three possible kinds of solutions, depending on the location of T with respect to A and B: 1. The solution has two points if the loci intersect. 2. The solution has one point if the perpendicular bisector is tangent to the circle. 3. The solution has no points if the perpendicular bisector does not meet the circle.

12.15 Write a program that uses the set f ( ) , f i 11( > , and width ( > functions to produce the following formatted output: